Denovo solution - Revision history

Mick at 10:18, 26 November 2025

2025-11-26T10:18:15Z

Gabre at 13:02, 29 November 2024

2024-11-29T13:02:40Z

← Older revision		Revision as of 15:02, 29 November 2024
Line 42:		Line 42:


	it is the Beta-galactosidase gene of E.Coli.		it is the Beta-galactosidase gene of E.Coli. That gene was used by François Jacob, André Lwoff and Jacques Monod to describe gene regulation in 1960 which got them the [https://www.nobelprize.org/prizes/medicine/1965/summary/ Nobel prize in 1965]
	<!-- Q14. The 454 assembly was best. -->		<!-- Q14. The 454 assembly was best. -->

Gabre at 12:55, 29 November 2024

2024-11-29T12:55:59Z

@@ Line 26: / Line 26: @@
 Q12. This is a region with a lot of repeats, this is also why we can't really assemble it. It is used by V. cholerae to integrate new genes into its genome.
-Q13. The Nanopore assembly only has 2 contigs and pacbio 1!
+Q13. Using:
 <!-- Q14. The 454 assembly was best. -->

Gabre at 14:49, 28 November 2024

2024-11-28T14:49:25Z

← Older revision		Revision as of 16:49, 28 November 2024
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	Q6. 1		Q6. 1

	Q7. Repeat regions + ~~missamblies~~		Q7. Repeat regions + misassemblies

	Q8. Contaminations + ~~missamblies~~		Q8. Contaminations + misassemblies

	Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.		Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.

	Q10. This is just visual, but it seems that ~~most~~ of the reference genome is covered by our assembly, so yes.		Q10. This is just visual, but it seems that a lot of the reference genome is covered by our assembly, so yes.

	Q11. ~~Yes, a couple of the small contigs does not map at all,~~ and the ~~C1097~~ only maps partially. This could be sequence in our strain, but not in the reference genome.		Q11. very few and the K119.81 only maps partially. This could be a sequence in our strain, but not in the reference genome. Or a misassembly.

	Q12. This is a region with a lot of repeats, this is also why we ~~cant~~ really assemble it. It is used by V. cholerae to integrate new genes into its genome.		Q12. This is a region with a lot of repeats, this is also why we can't really assemble it. It is used by V. cholerae to integrate new genes into its genome.

	Q13. The Nanopore assembly only has 2 contigs and pacbio 1!		Q13. The Nanopore assembly only has 2 contigs and pacbio 1!

	<!-- Q14. The 454 assembly was best. -->		<!-- Q14. The 454 assembly was best. -->

Gabre at 14:16, 28 November 2024

2024-11-28T14:16:09Z

← Older revision		Revision as of 16:16, 28 November 2024
Line 14:		Line 14:
	Q6. 1		Q6. 1

	Q7. Repeat regions		Q7. Repeat regions + missamblies

	Q8. Contaminations		Q8. Contaminations + missamblies

	Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.		Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.

Gabre at 12:23, 28 November 2024

2024-11-28T12:23:05Z

← Older revision		Revision as of 14:23, 28 November 2024
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	Q4. Mean = 259 ; SD = 11		Q4. Mean = 259 ; SD = 11

	Q5. It is ~~lower, this means that~~ the ~~actual kmer peak~~ we found ~~(unless you found one higher than 84) is higher (this would give a lower genome size).~~		Q5. It is higher N50:179846 than the best we found at k=79 N50:92020

	Q6. 10 of 195 contigs were scaffolded into scaffolds, this is quite few - normally it is much higher. A reason for this could be that our insert size is quite low (~250 bp) and the repeats in the genome are larger than this.		Q6. 1

	Q7. Repeat regions		Q7. Repeat regions

Gabre at 12:04, 28 November 2024

2024-11-28T12:04:05Z

← Older revision		Revision as of 14:04, 28 November 2024
Line 20:		Line 20:
	Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.		Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.

	Q10. This is ~~of course~~ just visual, but it seems that most ~~part~~ of the reference genome is covered by our assembly, so yes.		Q10. This is just visual, but it seems that most of the reference genome is covered by our assembly, so yes.

	Q11. Yes, a couple of the small contigs does not map at all, and the C1097 only maps partially. This could be sequence in our strain, but not in the reference genome.		Q11. Yes, a couple of the small contigs does not map at all, and the C1097 only maps partially. This could be sequence in our strain, but not in the reference genome.

WikiSysop: Created page with "Q1. Illumina Q1A. discarded contains reads that are too short, pair1 and pair2 files contain the read pairs were both passed trimming and singleton are reads were one of the two pairs were discarded. Q2. Around 84 Q3. N = (ML)/(L-K+1) = (8499)/(99-15+1) = 97.84 Genome_size = T/N = (213721367+212523694)/97.84 = 4.35Mb Q4. Mean = 259 ; SD = 11 Q5. It is lower, this means that the actual kmer peak we found (unless you found one higher than 84) is higher (this would g..."

2024-03-19T15:35:07Z

Created page with "Q1. Illumina Q1A. discarded contains reads that are too short, pair1 and pair2 files contain the read pairs were both passed trimming and singleton are reads were one of the two pairs were discarded. Q2. Around 84 Q3. N = (M*L)/(L-K+1) = (84*99)/(99-15+1) = 97.84 Genome_size = T/N = (213721367+212523694)/97.84 = 4.35Mb Q4. Mean = 259 ; SD = 11 Q5. It is lower, this means that the actual kmer peak we found (unless you found one higher than 84) is higher (this would g..."

New page

Q1. Illumina

Q1A. discarded contains reads that are too short, pair1 and pair2 files contain the read pairs were both passed trimming and singleton are reads were one of the two pairs were discarded.

Q2. Around 84

Q3. N = (M*L)/(L-K+1) = (84*99)/(99-15+1) = 97.84
Genome_size = T/N = (213721367+212523694)/97.84 = 4.35Mb

Q4. Mean = 259 ; SD = 11

Q5. It is lower, this means that the actual kmer peak we found (unless you found one higher than 84) is higher (this would give a lower genome size).

Q6. 10 of 195 contigs were scaffolded into scaffolds, this is quite few - normally it is much higher. A reason for this could be that our insert size is quite low (~250 bp) and the repeats in the genome are larger than this.

Q7. Repeat regions

Q8. Contaminations

Q9. Because we use the reference genome as the truth it may be hard to distinguish what is a misassembly and what is true variation from the reference genome.

Q10. This is of course just visual, but it seems that most part of the reference genome is covered by our assembly, so yes.

Q11. Yes, a couple of the small contigs does not map at all, and the C1097 only maps partially. This could be sequence in our strain, but not in the reference genome.

Q12. This is a region with a lot of repeats, this is also why we cant really assemble it. It is used by V. cholerae to integrate new genes into its genome.

Q13. The Nanopore assembly only has 2 contigs and pacbio 1!